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Lana71 [14]
3 years ago
10

A train left for Houston, and 7 hours later, a car traveling 62 mph tried catching up to the train. After 4 hours, the car caugh

t up. What was the train's average speed?
Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer: 22.55 mph

Step-by-step explanation:

Let the speed of the train be n

4 × 62 = 248 which is the distance travelled by the car in 4 hours and the train travelled in 11 hours

11 × n = 248

11n = 248

n = 248/11

n = 22.55mph

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Clint's salary increased from ​$24000 to $36000 over a​ three-year period.​ Helen's salary increased from ​$29000 to $43, 500 ov
lesya [120]

<u>Answer:</u>

Helen's salary increased more.

<u>Step-by-step explanation:</u>

We know that Clint's salary increased from ​$24000 to $36000 over a​ three-year period.​

So the increase in Clint's salary will be = 36000 - 24000 = $12000

While Helen's salary increased from ​$29000 to $43, 500 over the same period of 3 years.

So the increase in Helen's salary will be = 43500 - 29000 = $14500

Therefore, in absolute terms, Helen's salary has increased more.

8 0
4 years ago
Help me pls thankyouuuuuuu
torisob [31]

Answer: 4\sqrt[3]{4}

Step-by-step explanation:

8 0
3 years ago
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Chelsea spent half of her weekly
Anvisha [2.4K]

Answer:

I believe it would be 16

Step-by-step explanation:

8 is half of 16 and if she had 8 dollars after spending half her allowance, she would've had 16 as her allowance

Final answer: Her allowance would be 16 dollars

3 0
3 years ago
What is the probability that a group of five friends all have different birthdays? Show all of your work for full credit.
patriot [66]

Answer: 0.98630136986

Step-by-step explanation:

There are 365 possible birthdays. The key to assigning the probability is to think in terms of complements: “Two (or more) people share a birthday” is the complement of “All people in the group have different birthdays.” Each probability is 1 minus the other. What is the probability that any two people have different birthdays? The first person could have any birthday (p = 365÷365 = 1), and the second person could then have any of the other 364 birthdays (p = 364÷365). Multiply those two and you have about 0.9973 as the probability that any two people have different birthdays, or 1−0.9973 = 0.0027 as the probability that they have the same birthday. If you have a group of five, it would mean your equation would have to be (p=360÷365)

8 0
3 years ago
Question
ladessa [460]

Answer:

Step-by-step explanation:

4s + 2j = 68........2j = -4s + 68........j = -2s + 34

3s + 3j = 81

3s + 3(-2s + 34) = 81

3s - 6s + 102 = 81

3s - 6s = 81 - 102

-3s = - 21

s = -21/-3

s = 7 <==== shirts cost 7 bucks

j = -2s + 34

j = -2(7) + 34

j = -14 + 34

j = 20 <===== jeans cost 20 bucks

7 0
3 years ago
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