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Lana71 [14]
3 years ago
10

A train left for Houston, and 7 hours later, a car traveling 62 mph tried catching up to the train. After 4 hours, the car caugh

t up. What was the train's average speed?
Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer: 22.55 mph

Step-by-step explanation:

Let the speed of the train be n

4 × 62 = 248 which is the distance travelled by the car in 4 hours and the train travelled in 11 hours

11 × n = 248

11n = 248

n = 248/11

n = 22.55mph

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Initially, there were only 197 weeds at a park. The weeds grew at a rate of 25% each week. The following function represents the
olganol [36]

Answer:

 none of the above

 f(x) ≈ 197·1.03^x; approximately 3% daily

Step-by-step explanation:

If we let x represent days, then x/7 represents weeks and we can rewrite f(x) as ...

 f(x/7) = 197·1.25^(x/7) = 197·(1.25^(1/7))^x

 f(x) ≈ 197·1.03^x

__

The daily multiplier of 1.03 represents a daily growth rate of

 1.03 -1 = .03 = 3%

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These answers are not found among the offered choices:

f(x) = 197·1.03^x

3% daily growth

Step-by-step explanation:

8 0
3 years ago
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What is the average rate of change of h over the interval (2,6) ?<br> Give an exact number.
Viktor [21]

Answer:

3

Step-by-step explanation:

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3 years ago
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1500+1500 please answer
ehidna [41]
3000 is the freaking right answer
7 0
3 years ago
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Please help!
crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

4 0
3 years ago
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