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Ksenya-84 [330]
3 years ago
5

How many neutrons does element X have if it’s atomic number is 33 and it’s mass number is 93?

Physics
2 answers:
Luba_88 [7]3 years ago
6 0
To find the neutrons, subtract the atomic number from the atomic mass.

Atomic mass - Atomic number = Neutrons

93 - 33 = 60

Element X has 60 neutrons.
Nataly [62]3 years ago
3 0
Element X has 60 nutrons

93-33=60
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tensa zangetsu [6.8K]

Answer:

Electric field at a distance of 1.45 cm will be 172.41\times 10^4N/C

Explanation:

We have given the distance d = 1.45 cm = 0.0145 m

And the potential difference V=2.5\times 10^4volt

There is a relation between potential difference and electric field

Electric field at a distance d due to a potential difference is given by

E=\frac{V}{d}, here E is electric field, V is potential difference and d is distance

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Mady has an infinite number of balls and empty boxes available to her. The empty boxes, each capable of holding four balls, are
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Answer:

The number of balls in the box at 2010th step is 6 balls

Explanation:

Since the boxes are arranged from left to right, and since the empty boxes are capable of holding 4 balls at once.

Therefore, her steps would follow this pattern ;

00001 - 1st Step

0002 - 2nd Step

0003 - 3rd Step

0004 -4th Step

0010 - 5th Step

0011 - 6th Step

0021 - 7th step

0031 - 8th step

0041 - 9th step

Looking at this pattern, it is obvious this digits are in base 5 because once we count to 4 in a unit, we move to the next at 1.

Thus,at Mady's 2010th step, we'll convert to base 5,thus 2010 in base 5 is calculated as;

2010 ÷ 5 = 402 r 0, so Base 5 is now: _ _ _ _ 0.

402 ÷ 5 = 80 r 2, so Base 5 is now: _ _ _ 2 0.

80 ÷ 5 = 16 r 0, so Base 5 is now:

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16 ÷ 5 = 3 r 1, so Base 5 is now: _ 1 0 2 0.

3 ÷ 5 = 0 r 3, so Base 5 is now: 3 1 0 2 0.

So 2010 in base 10 is 31020 in base 5. Thus,the number of balls in the box at 2010th step is equal to 3 + 1 + 0 + 2 + 0 = 6balls

3 0
3 years ago
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maksim [4K]

Answer:

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4 0
4 years ago
What is the meaning of physic​
irina [24]

the scientific study of natural forces such as light, sound, heat, electricity, pressure, etc.

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3 years ago
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Answer:

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The most correct answer is:

* Propagation of pressure fluctuations in a medium

Part b

air is the medium in which the wave is transported, otherwise it cannot propagate

8 0
3 years ago
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