A. Dashed Line B. Solid Line
1 answer:
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Answer:
1. 3
2. 1.5
3. 3 seconds
4. 0
5. 2.2 seconds
Explanation:
(1)
From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.
Making a the subject we have
Substituting u=0 since it’s at rest, v=30m/s and t=10 seconds
a =
(2)
From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.
Making a the subject we have
Substituting u=10m/s, v=22m/s and t=8 seconds
a =
(3)
From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.
Making t the subject we have
Substituting u=0m/s since at rest, v=15m/s and a=5
=
(4)
When initial and final velocity are constant, there’s no acceleration as proven below
From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.
Making a the subject we have
Substituting u=20 since it’s at rest, v=20m/s and t=10 seconds
a =
(5)
From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.
Making t the subject we have
Substituting u=9m/s since at rest, v=0m/s and a=-4.1
=
The given in this problem is that two balls are thrown at different times, different heights and velocities. A blue ball is thrown upward at a specific velocity at a lower altitude while a red ball is thrown downwards at a specific speed and at a higher height. In this case, we are asked here to describe the graph of the behavior of the balls as a function of time. The x-axis then is time while the y-axis is the velocity of the ball. The blue ball has a quadratic function while the red ball is more or less exponential. See the attached figure for reference.
