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torisob [31]
3 years ago
6

If 10. joules of work must be done to move 2.0 coulombs of charge from point A to point B in an electric field, the potential di

fference between points A and B is
Physics
1 answer:
masya89 [10]3 years ago
8 0
The equation for work (W) done by an electric field is:

W = qΔV

where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:

10 = 2ΔV
ΔV = 5
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The  angle is  \theta  =  15.48^o

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     The time taken is  t =  0.455 \ s

   

The  horizontal component of the speed of the dart is mathematically represented as

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substituting values

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From projectile kinematics the time taken by the dart can be mathematically represented as

         t  =  \frac{2usin \theta }{g}

=>    usin \theta =  \frac{g  * t}{2 }

       usin \theta =  \frac{9.8  * 0.455}{2 }

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=>   tan \theta =  \frac{usin\theta }{ucos \theta }  =  \frac{2.23}{8.04}

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Can a object have have zero velocity and nonzero acceleration?
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yes

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