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svetlana [45]
4 years ago
13

If the coolant in an air conditioner has a lower temperature than the air in a building, then ____.

Physics
2 answers:
solmaris [256]4 years ago
8 0
Heat always flows from higher temperature to lower temperature. So option A. heat will flow from the air into the coolant is the correct answer.

katen-ka-za [31]4 years ago
3 0
<span>A. heat will flow from the air into the coolant</span>
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A flat loop of wire consisting of a single turn of cross-sectional area 7.10 cm2 is perpendicular to a magnetic field that incre
MAVERICK [17]
<span>From Ohm's law. V = IR. Where R = 2 Ohms. To calculate the induced current I; We need to calculate the electromotive force or voltage, V. From Faraday's law induced EMF = (The rate of change of magnetic flux density x Area)/ (changein time). Or EMF = BA/t. Where B = Bf - Bi. And BA = Bf* A - Bi* A. Bf = 2.00 and Bi = 0.500 and t = 0.93s and the area, A = 7.1 cm^2 is 0.000071 m^2. 2 So Emf = 2.00 (0.000071) - 0.500(0.000071) /(0.93) = 1.0654 * 10^(-4)/ 0.93 = 1.1415 * 10^(-4). Substituting into ohms law, we have, I = (1.1415 * 10^(-4)) / 2 = 0.57075 * 10^(-4)</span>
3 0
3 years ago
A window washer drops a brush from a scaffold on a tall office building. What is the speed of the falling brush after 3.28 s? (N
valina [46]

Answer:

The speed of washer will be 32.144 m/s

Explanation:

Given that

time t= 3.28 s

Acceleration due to gravity

 g=9.8\ \frac{m}{s^2}

Here acceleration  is constant so we cam apply the motion equation

we know that

v= u + at

At initial condition  u =0 m/s

v= u + at

v= 0 + 9.8 x 3.28

v= 32.144 m/s

So the speed of washer will be 32.144 m/s

6 0
3 years ago
Read 2 more answers
Se deja caer una pelota inicialmente en reposo desde una altura de 50m sobre el nivel del suelo. ¿cuanto tiempo requiere para ll
umka2103 [35]

Answer:

a) t = 3.2 s

b) v_{f} = -32 m/s

Explanation:

a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:

t = \sqrt{\frac{2y_{0}}{g}}

En donde:

y_{0}: es la altura inicial = 50 m

g: es la gravedad = 10 m/s²

t = \sqrt{\frac{2y_{0}}{g}} = \sqrt{\frac{2*50 m}{10 m/s^{2}}} = 3.2 s

Entonces, el tiempo requerido para llegar al suelo es 3.2 s.

b) La rapidez de la pelota justo antes del choque es el siguiente:

v_{f} = v_{0} - gt

En donde:

v_{0}: es la velocidad inicial = 0 (dado que se deja caer en resposo)

v_{f} = v_{0} - gt = 0 - 10 m/s^{2}*3.2 s = -32 m/s

Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).

Espero que te sea de utilidad!

6 0
3 years ago
Convert 100 degrees C to Kelvin SHOW ALL WORK
Tanzania [10]

Answer:

373 K

Explanation:

K = C° + 273

K = 100° + 273 ➡ 373 K

3 0
4 years ago
calculate the densities of the following materials. Material A has a volume of 2 cm 3 and mass of 30 g.​
vladimir2022 [97]

Answer:

0.015kgcm^3

Explanation:

density = mass / volume

density = (30/1000) / 2

= 0.015kgcm^3

8 0
4 years ago
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