Answer:
There are many types of information al references such as Encyclopedias, dictionaries, thesaurus Almanacs, atlases, thesauruses, Atlases, almanacs, and encyclopedias.
Explanation:
There are also informational websites. The way to find this is to look at the website url to see if it ends in .gov, .edu, and .org . But make sure you cite your source so you don't plagiarize.
If you don't have any questions feel free to ask in the comments.
Answer:
The blocking system.
Explanation:
In order to avoid servers to replicate with each other, I should configure the blocking system of the first DHCP.
For example, if the first DHCP fails to respond, the second will get in place, however, I have to configure the first system that immediately that the second DHCP starts working, the first blocks its information and use.
By this way, there won´t be any duplicated actions or reponses.
Answer:
Research what kind of computer you want.
Explanation:
I don't know exactly what you are asking here but when doing research you have got to know what you want like how much ram you want, how much storage you want, what brand of computer you want, what core processor you want, and what graphics card you want. You also have to decide if you want a laptop or a full sized desk top computer.
Answer:
#include <iostream>
#include <string>
#include <stack>
#include <math.h>
using namespace std;
int main() {
string s;
double n=0;
int position=0;
stack<int> wholeNumbers;
cout<<"Enter a decimal number:";
cin>>s;
string::iterator counter = s.begin();
while(*counter!='.' && counter!=s.end()){
wholeNumbers.push(*counter-48);
counter++;
position=position+1;
}
for(int i=0;i<position;i++){
n=n+(wholeNumbers.top()*pow(10,i));
wholeNumbers.pop();
}
position=-1;
if(counter!=s.end()){
counter++;
}
while(counter!=s.end()){
n=n+((*counter-48)*pow(10,position));
position=position-1;
counter++;
}
cout<<n;
}
Explanation:
- Inside the while loop, push the push a number to the wholeNumbers stack by subtracting it with 48.
- Increment the counter and position variable by 1 inside the while loop.
- Count the number of digit, push each digit to top of stack and find the end of the number,
- Run a for loop up to the value of position variable and pop a value from the wholeNumbers stack.
