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Dmitriy789 [7]
3 years ago
6

The use of themes in WordPress is a good illustration of what major concept?

Computers and Technology
1 answer:
NemiM [27]3 years ago
8 0

Answer:

Front-End Development

Explanation:

This is what the consumer will see and interact with such as the theme.

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Answer:

r u Kate tell me plz I love u baby tell me please

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3 years ago
Write the interface (.h file) of a class Counter containing: A data member counter of type int. A data member named counterID of
OlgaM077 [116]

Explanation:

See the attached image for The interface (.h file) of a class Counter

8 0
3 years ago
What is the correct process for selecting an entire row in a spreadsheet?
Valentin [98]
A. Click on any cell in the row
7 0
3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
c++ Write a statement that increments (adds 1 to) one and only one of these five variables: reverseDrivers parkedDrivers slowDri
Mazyrski [523]

Answer:

The following statement are:

if(speed < 0) // if statement

{

reverseDrivers++; //if the speed is less than 0, then increment in "reverseDrivers"

}

else if(speed < 1) //else if statement

{

parkedDrivers++; //speed is less than 1, than increments in "parkedDrivers"

}

else if(speed < 40)

{

slowDrivers++; //speed is less then 40, than increment in "slowDriver"

}

else if(speed <= 65)

{

safeDrivers++; //speed is less than or equal to 40, then increment in "safeDriver"

}

else

{

speeders++; //else increment in speeders

}

Explanation:

From the following statement their are certain condition arises

If the speed is less than 0, then increments the “reverseDrivers” variable by 1.

If the speed is less than 1, then increments the “parkDriver” variable by 1.

If speed is less than 40, then increment in "slowDriver" variable by 1.

If speed is less than or equal to 40, then increment in "safeDriver" variable by 1.

Otherwise increment in "speeders"

7 0
3 years ago
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