Which of the reagents listed below would efficiently accomplish the transformation of ethyl-3-pentenoate into 3-penten-1-ol?

Chemistry

1 answer:

Mandarinka [93]4 years ago

7 0

Reactions of Ethyl-3-pentenoate with all given reagents are given below.

Reaction with H₂ / Pd:
The non-polar double bond present in Ethyl-3-pentenoate is reduced to saturated chain. This reagent can not reduce the carbonyl group.

Reaction with NaBH₄:
Sodium Borohydride is a weak reducing agent at compared to LiAlH₄. It can only reduce aldehydes and Ketones to corresponding alcohols.

Reaction with LiAlH₄:
Lithium Aluminium hydride is a strong reducing agent. It can reduce all types of carbonyl compounds to corresponding alcohols, But, it can not reduce non-polar double bonds like alkenes and alkynes.

Result:
The correct answer is Option-A (Highlighted RED below).

You might be interested in

For the given reactions, classify the reactants as the reducing agent, oxidizing agent, or neither.

3241004551 [841]

Answer: For $F_{2} + H_{2} \rightarrow 2HF$ , $F_{2}$ is the oxidizing agent and $H_{2}$ is the reducing agent.

For $2Mg + O_{2} \rightarrow 2MgO$ , Mg is the reducing agent and $O_{2}$ is the oxidizing agent.

Explanation:

An oxidizing agent is defined as the substance which tends to oxidize other substances by itself gaining electrons. As a result, there will occur a decrease in its oxidation state.

On the other hand, a substance which tends to reduce other substances by itself losing electrons is known as an reducing agent. There will occur an increase in oxidation state of a reducing agent.

For example, $F_{2} + H_{2} \rightarrow 2HF$

Oxidation: $H_{2} \rightarrow 2H^{+} + 2e^{-}$