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3 years ago

Pls pls pls pls pls pls pls pls pls pls pls help help help help help help help help help help

Chemistry

1 answer:

Gwar [14]3 years ago

6 0

Answer:

Explanation:

The moon would fall and earth as well

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Eddi Din [679]

Answer:

С. form chains or rings by bonding to itself and other atoms.

Explanation:

Carbon is an element in group 4 of the periodic table with unique bonding properties. Carbon posseses 4 valence electrons in its outer shell. This enables carbon to form covalent bonds with the atoms of other elements e.g. nitrogen, phosphorus, oxygen, hydrogen etc.

Carbon can also combine covalently with other carbon atoms i.e. C-C to form long chains and rings in a process called CATENATION. This unique property of carbon makes it the only element that can form so many different compounds.

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3 years ago

Part B Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, Be.

dmitriy555 [2]

Answer: The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

Explanation:

There are 4 quantum numbers:

Principal Quantum number (n) specifies the energy of the electron in a shell.
Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of $+\frac{1}{2}$ or $-\frac{1}{2}$

Berylium (Be) is the 4th element of periodic table having electronic configuration of $1s^22s^2$

For electrons in 1s-orbital, the quantum numbers can be:

For first electron:

$n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=1\\l=0\\m=0\\s=-\frac{1}{2}$

For electrons in 2s-orbital, the quantum numbers can be:

For first electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}$

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

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