Given data:
Concentration of stock solution which is the initial solution = M1 = 1.00 * 10^3 mg/L
Concentration of prepared solution i.e final solution = M2 = 6.250 mg/L
Volume of final solution, V2 = 5.000 * 10^2 ml
To determine:
The initial volume i.e. volume of the stock solution required = V1
Calculation:
Use the relation
M1V1 = M2V2
V1 = M2V2/M1 = 6.250 mg.L-1 * 5.000*10^2 ml/1.00 * 10^3 mg.L-1
V1 = 3.125 *10^3 ml
The volume of stock solution required is 3.125 *10^3 ml
Answer: hello your question has some missing details attached below is the missing details
answer : 25.5% ( B )
Explanation:
<u>Determine percentage yield </u>
molar mass = 35 g/mol
mass of Li₃N(s) = 70 g
product LiH(s) = 8.0 g ( actual yield )
theoretical yield ( LiH ) = 4 * 7.95 = 31.8 g
percentage yield = actual yield * 100 / theoretical yield
= 8 * 100/31.8
= 25.5%
100kpa is correct If that is not wht you were asking i'd gladly fix it :)
1. Ph is a figure used to measure the alkalinity or acidity of something. 7 is the neutral figure while lower numbers mean that the thing is more acidic. Higher numbers mean the thing is has more alkaline in it.
2. 7.35 is the ideal Ph of blood.