Question

For the given reactions, classify the reactants as the reducing agent, oxidizing agent, or neither.

Answer 1

Answer: For $F_{2} + H_{2} \rightarrow 2HF$, $F_{2}$ is the oxidizing agent and $H_{2}$ is the reducing agent.

For $2Mg + O_{2} \rightarrow 2MgO$, Mg is the reducing agent and $O_{2}$ is the oxidizing agent.

Explanation:

An oxidizing agent is defined as the substance which tends to oxidize other substances by itself gaining electrons. As a result, there will occur a decrease in its oxidation state.

On the other hand, a substance which tends to reduce other substances by itself losing electrons is known as an reducing agent. There will occur an increase in oxidation state of a reducing agent.

For example, $F_{2} + H_{2} \rightarrow 2HF$

Oxidation: $H_{2} \rightarrow 2H^{+} + 2e^{-}$

Reduction: $F + 1e^{-} \rightarrow F^{-}$

Hence, here $F_{2}$ is the oxidizing agent and $H_{2}$ is the reducing agent.

Also,

     $2Mg + O_{2} \rightarrow 2MgO$

Oxidation: $Mg \rightarrow Mg^{2+} + 2e^{-}$

Reduction: $O_{2} + 2e^{-} \rightarrow O$

Hence, here Mg is the reducing agent and $O_{2}$ is the oxidizing agent.