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OleMash [197]
3 years ago
15

Help with this plzzzzzzzzzzzzzz

Mathematics
1 answer:
kupik [55]3 years ago
3 0

Answer: 4^0

Step-by-step explanation:

4^5*4^-^7/4^-^2

Rewriting this;

\frac{4^5*4^-^7}{4^-^2}

When you multiply by the same base, you add exponents.

\frac{4^5^+^(^-^7^)}{4^-^2}

\frac{4^5^-^7}{4^-^2}

\frac{4^-^2}{4^-^2}

When you divide by the same base, you subtract exponents.

4^-^2^-^(^-^2^)

4^-^2^+^2\\4^0

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How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
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The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

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For the first wave

f = 20 waves/sec

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λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

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The factor by which the first sound wave is longer than the second sound wave is

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= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

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1 year ago
In any triangle ABC, which of the relations
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Two angles are supplementary. One angle has a measure of 44 degrees. What is the measure of the other angle?
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