2 years ago

Help me please asap!!

Mathematics

2 answers:

In-s [12.5K]2 years ago

5 0

I’m sorry i do not know this

klemol [59]2 years ago

3 0

I’m sorry I don’t know this either

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Determine the radius and center of the circle with the following equation <br> x^2+y^2-12x+24y-10=6

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Answer:

Center: (6, -12)

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Step-by-step explanation:

<u>Complete the squares</u>

<u /> $x^2+y^2-12x+24y-10=6\\\\x^2-12x-10+y^2+24y=6\\\\x^2-12x-10+46+y^2+24y+144=6+46+144\\\\(x^2-12x+36)+(y^2+24y+144)=196\\\\(x-6)^2+(y+12)^2=196$

Comparing with the standard form equation $(x-h)^2+(y-k)^2=r^2$ , since $r^2=196$ , then the radius of the circle is $r=14$ . Also, the center of the circle would be $(h,k)\rightarrow(6,-12)$ .

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