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adoni [48]
3 years ago
11

Find the product (-7t+4)^2

Mathematics
1 answer:
iVinArrow [24]3 years ago
8 0
-113t
I think that’s the answer
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Calculate the perimeter of the following parallelogram:<br> 10 in<br> 4 in<br> 3 in
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3 because when you catch
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Solve by completing the square? Could you please work it out step-by-step?
DaniilM [7]
16 n^2 -10n + 129 = 8n^2 -8

We collect the terms:
8n^2 -10n + 137 = 0

The steps for completing the square:

1) Move the "non X" (or "non N") term to the right:

8n^2 -10n  = -137

<span>2)<span> Divide the equation by the coefficient of N² which in this case is 8
n^2 -1.2n = </span></span><span><span>-17.125 </span>

3) Take the coefficient of "N"; divide it by 2; square it; add it to both sides of the equation.
-1.2 / 2 = -.6
-.6^2 = .36

</span>
n^2 -1.2n +.36 = <span>-17.125 +.36

Take the square root of both sides:</span>
(n-.6)*(n-.6) = sq root( <span> <span> <span> -16.765 </span> </span> </span> )
That's about as far as I can go.

4 0
3 years ago
jamal is going to borrow $14,000 from his credit union to buy a used car. The APR is 7.0% and the length of the loan is 4 years.
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His total amount of interest will be $2,091.88
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Which is a better buy 4 grapefruits for 80 cents or 12 grapefruits for $1.80?
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12 grapefruit for 1.80. so if you multiply. 80 cents by 3=2.40 for 12 but 1.80 us cheaper
8 0
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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
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