11.) 4/5 * 3/4 = 12/20 reduces to 3/5
12.) 5 / (1/3) = 5 * 3 = 15
13.) 5 3/6 * 1 1/11 = 33/6 * 12/11 = 396/66 = 6
14.) 3 5/9 * 3/8 = 32/9 * 3/8 = 96/72 reduces to 4/3 or 1 1/3
15.) (2 5/6) / (1 1/2) = (17/6) / (3/2) = 17/6 * 2/3 = 34/18 reduces to 17/9 or
1 8/9.
16.) 24 / (2 3/4) = 24/(11/4) = 24 * 4/11 = 96/11 = 8 8/11
17.) 7 1/2 * 5 4/5...estimate : 8 * 6 = 48
18.) 9 8/15 * 11...estimate : 10 * 11 = 110
19.) (48 5/9) / (7 1/8)...estimate : 49/7 = 7
20.) (50 3/7) / (9 2/3)...estimate : 50/10 = 5
It would be positive. I hope this helped ^^
Q=56??? Sorry if it’s wrong lol
We can check the end terms first
for
(a+b)(c+d), the first term of the expanded is ac and the last term is bd
so
the expanded is x^3 and last is +7
jane will have a lst term of -7 so no
mariah wil have last term of -7 as well, so no
only rojer and nethan have last tem of +7
so we can do the rest of it by doing the OL part of FOIL
do either roger or nethan
let's do nethan
F=x^3
O=-7x
I=-x^2
L=7
yep
it is nethan
