Answer:
x
2
+6xy+9y
2
+4x+12y−5=0
Step-by-step explanation:
x
2
+6xy+9y
2
+4x+12y−5=0
Comparing the equation with the general equation of second degree gives
a=1,b=9,h=3,g=2,f=6,c=−5
Angle between a pair of straight lines that is tanθ=
∣
∣
∣
∣
∣
∣
a+b
2
h
2
−ab
∣
∣
∣
∣
∣
∣
tanθ=
∣
∣
∣
∣
∣
1+9
2
9−1×9
∣
∣
∣
∣
∣
=
9
0
tanθ=0
⇒θ=tan
−
(0)=0
∘
Angle between the pair of straight lines is zero therefore the lines are parallel.
Hence proved
Answer:
Step-by-step explanation:
Let the length of one side of the square base be x
Let the height of the box by y
Volume of the box V = x²y
Since the box is opened at the top, the total surface area S = x² + 2xy + 2xy
S = x² + 4xy
Given
S = 7500sq in.
Substitute into the formula for calculating the total surface area
7500 = x² + 4xy
Make y the subject of the formula;
7500 - x² = 4xy
y = (7500-x²)/4x
Since V = x²y
V = x² (7500-x²)/4x
V = x(7500-x²)/4
V = 1/4(7500x-x³)
For us to maximize the volume, then dV/dx = 0
dV/dx = 1/4(7500-3x²)
1/4(7500-3x²) = 0
(7500-3x²) = 0
7500 = 3x²
x² = 7500/3
x² = 2500
x = √2500
x = 50in
Since y = (7500-x²)/4x
y = 7500-2500/4(50)
y = 5000/200
y = 25in
Hence the dimensions of the box that will maximize its volume is 50in by 50in by 25in.
The Volume of the box V = 50²*25
V = 2500*25
V= 62,500in³
Hence the maximum volume is 62,500in³