Okay so molar mass is given, no. of moles is given and we have to calculate the weight or mass of the compound in gram.
the formula we will use here is= n=W/M
where n is no. of moles ,w is weight in gram which we have to find and M is molar mass or formula weight which is given.
so W=n x M
use this formula you'll get the answer
Atomic number, atomic mass, symbol of element
Answer:
5.83 mol.
Explanation:
- From the balanced reaction:
<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>
It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.
Al reacts with Ag₂S with (2: 3) molar ratio.
<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>
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- The limiting reactant is Ag₂S.
- The excess "left over" reactant is Al.
The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.
D
Boiling and melting are both physical changes so do not involve the formation or breakage of chemical bonds.
