Question

Please help I will mark as brainliest!!and explain.

Answer 1

The reaction that will take place is:

CuO + H₂SO₄ → CuSO₄ + H₂O (balanced)

Amount of Sulphuric acid provided:

we have 500 mL of a 0.5 molar solution of Sulphuric acid           (1 cm³ = 1mL)

We know that molarity is found with the formula:

Molarity = Number of Moles / Volume (in L)

let's plug the given values

0.5 = Number of moles / 0.5 L

Number of moles = 0.25 moles              [multiplying both sides by 0.5]

Amount of CuO reacted:

from the balanced equation, we know that CuO reacts with H₂SO₄ in a 1:1 ratio (1 mole of CuO reacts with 1 mole of H₂SO₄)

so 0.25 moles of H₂SO₄ (present in the solution) will react with 0.25 moles of CuO

Mass of 0.25 moles of CuO:

molar mass of CuO = 80 grams/mol (approx.)

we are aware of the relation:

Number of moles = Given mass / Molar mass

plugging the values we have:

0.25 = Mass / 80

Mass = 20 grams                               [multiplying both sides by 80]

Hence 20 grams of CuO will react