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Troyanec [42]
4 years ago
10

-3x-6+(-1) please help me

Mathematics
1 answer:
Sauron [17]4 years ago
4 0

Answer:

I think its -3x-7



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What equation results from completing the square and then factoring? x^2+24x=33
Nezavi [6.7K]

Answer:

Its C but the way I got is too small so I cant really give explanation

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Peter wallpapered a wall that was 9 feet wide and 8 feet high. He had 27 square feet of wallpaper left over. How many square fee
ivanzaharov [21]

Answer:

99 square feet

Step-by-step explanation:

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3 years ago
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Liz received a gift of 9 songs for her birthday. She buys an additional 3 songs each month.
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9+3

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Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
3 years ago
Nick paid 2.94 in sales tax on an item that cost $42.00 at the rate how much he pay in sales tax on an item that cost $58.00 bef
ruslelena [56]
$2.93/$42= about 7% tax
$58*7%= $<span>4.06 in tax</span>
4 0
4 years ago
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