Answer:
C.I = 0.7608 ≤ p ≤ 0.8392
Step-by-step explanation:
Given that:
Let consider a random sample n = 400 candidates where 320 residents indicated that they voted for Obama
probability 
= 0.8
Level of significance ∝ = 100 -95%
= 5%
= 0.05
The objective is to develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.
The confidence internal can be computed as:

where;
=
= 1.960
SO;






= 0.8 - 0.0392 OR 0.8 + 0.0392
= 0.7608 OR 0.8392
Thus; C.I = 0.7608 ≤ p ≤ 0.8392
Answer is 1 1/12
3(1/4 + 1/2^2)+ (2x1/12)
3/4+1/4+2/12 (you get to this part by distributing 3 throughout the parentheses)
9/12+3/12+2/12= 1 1/12 hope this helps
184,000 can be rounded by underlining the 3 in the thousands place and look to the right. if, it is more than 5 add 1 to the left, 184.... then replace the numbers behind the rounded number, will be 0. 184,000
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Answer: it’s B
Step-by-step explanation: It’s not a or c so... PERIOD