Length would be 362.5
He width would be 1087.5
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Answer:520; 240
Step-by-step explanation:
a. 13, 26, 39, 52,......
a = First term = 13
d = common difference = 26 - 13 = 13
40th term = a + (n - 1)d = a + (40-1)d = a + 39d
= 13 + (39 × 13)
= 13 + 507
= 520
b. 6, 12, 18, 24,.......
a = First term = 6
d = common difference = 12 - 6 = 6
40th term = a + 39d
= 6 + 39(6)
= 6 + 234.
= 240
The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.
<h3>What are permutation and combination?</h3>
A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.
It is given that:
On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:
The required number of ways:
= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))
= 2[2[ 1 + 5 + 15+35] + 70]
= 364
Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.
Learn more about permutation and combination here:
brainly.com/question/2295036
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Answer:
A for the first and C for the second
Step-by-step explanation:
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