By conservation of momentum,
(110.0 kg) (1.5 ms⁻¹) + (170.0 kg) (-2.0 ms⁻¹) = (110.0 kg) (-2.75 ms⁻¹) + (170.0 kg) v
where v is the final velocity of the second car.
Solve for v :
-175 kg•ms⁻¹ = -302.5 kg•ms⁻¹ + (170.0 kg) v
127.5 kg•ms⁻¹ = (170.0 kg) v
v = (127.5 kg•ms⁻¹) / (170.0 kg) = 0.75 ms⁻¹
Answer: the answer is x=3
Step-by-step explanation: let me know if u need to know how I got x=3
Answer:
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Step-by-step explanation:
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