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allsm [11]
2 years ago
7

Help please I need help please

Mathematics
1 answer:
77julia77 [94]2 years ago
7 0
Sum every temperature of every month and divide it by the number of months, so 12
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Law of sines: How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3?
butalik [34]
According to the law of sines:

\frac{a}{sin(A)} = \frac{b}{sin(B)}

Using the given values, we can find the angle B and find the number of possible triangles that can be formed.

\frac{2}{sin(75)}= \frac{3}{sin(B)} \\  \\ 
sin(B)=3* \frac{sin75}{2}  \\  \\ 
sin(B)=1.45 \\  \\ 
B=sin^{-1} (1.45)

The range of sin is from -1 to 1. The above expression does not yield any possible value of B, as sin of no angle can be equal to 1.45.

Therefore, we can conclude that no triangle exists with the given conditions.
5 0
3 years ago
Apakah kesan kedudukan tersebut terhad
Lena [83]

ABB G Ppppwhbbbsbbsbsbsbsjsjkskenennsn

4 0
3 years ago
THE X-INTERCEPT OF THE LINE X=3.5 IS
tiny-mole [99]
Well.. for the equation x= 3.5, let's take a look at its values
\bf \begin{array}{lrlll}
x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
3.5&-\infty\\
3.5&-1,000,000\\
3.5&-1,000\\
3.5&-100\\
3.5&-10\\
3.5&-1\\
3.5&0\\
3.5&1\\
3.5&10\\
3.5&100\\
3.5&1,000\\
3.5&1,000,000\\
3.5&1+\infty
\end{array}

so.. notice.. no matter what "y" is, "x"  will always be 3.5,
so is really just a horizontal line, thus, look at the picture below

8 0
4 years ago
What value of x makes this equation true?
Softa [21]
Well you gotta find out what x means
3 0
3 years ago
Jason has 5 shirts for every 2 pairs of pants. His brother John has 7 shirts for every 3 pairs of pants. Compare the ratio by co
postnew [5]

Answer:

john has a greater ratio of shirts to pants

Step-by-step explanation:

jason- 5:2

table:

shirt :5 10 15 20 25 30 35 40 45

pants:2 4   6   8   10 12  14 16 18 20

john-7:3

table:

shirts:7 14 21 28 35 42 49 56 63

pants:3  6 9 1 2  15  18  21 24  27

4 0
3 years ago
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