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Kobotan [32]
3 years ago
11

The perimeter of a rectangle is 16 inches. The equation that represents the perimeter of the rectangle is 2l + 2w = 16, where l

represents the length of the rectangle and w represents the width of the rectangle. Which value is possible for the length of the rectangle?
Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0
2(l+w)=16
l+w=16:2
l+w=8

for l>w

l=7, w=1
l=6, w=2
l=5, w=3 
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6 0
2 years ago
The points (6, -3) and (7, -10) fall on a particular line. What is its equation in point-slope form? Use one of the specified po
kumpel [21]

Answer:

Step-by-step explanation:

Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;

The standard equation of a line is y = mx+c

m is the slope

c is the intercept

Get the slope;

m = Δy/Δx = y2-y1/x2-x1

m = -10-(-3)/7-6

m = -10+3/1

m = -7

Get the intercept;

Substitute the point (6, -3) and m = -7 into the expression y = mx+c

-3 = -7(6)+c

-3 = -42 + c

c = -3 + 42

c = 39

Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c

y = -7x + 39

Hence the required equation is y = -7x + 39

6 0
3 years ago
Fred buys a video game disk for $4. There was a discount of 20%. What is the sales price?
dem82 [27]
4*20%
4*.2=
.8
4-.8=
3.2
The sales price would be $3.20

7 0
3 years ago
Please help! thank you to anyone who does:)
Sav [38]

Answer: it is th

Step-by-step explanation:

3 0
3 years ago
8.The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb. The
Sladkaya [172]

Answer:

The value is c = 21.1445.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb.

This means that \mu = 12, \sigma = 3.5

What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight?

This 1 added to the value of X for the 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 12}{3.5}

X - 12 = 2.327*3.5

X = 20.1445

1 + 20.1445 = 21.1445

The value is c = 21.1445.

7 0
3 years ago
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