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3 years ago

Write a decimal problem that requiers regrouping to slove.solve it

Mathematics

1 answer:

Vilka [71]3 years ago

4 0

95.84
89.82
---------
185.66
you add decimals the same way as whole numbers but make sure the decimals are aligned

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I need help asap :):):):

Kamila [148]

Answer:

its the second one

Step-by-step explanation:

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3 years ago

Together, Katya and Mimi have 480 pennies in their piggy banks. After Katya lost ½ of her pennies and Mimi lost 2/3 of her penni

labwork [276]

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3 years ago

Help please!!!!!

Sergio [31]

Answer:

a. image 1

Step-by-step explanation:

<u>Given function:</u>

f(x) = 2*3ˣ

<u>Plot two points and check which graph has those:</u>

f(0) = 2*3⁰ = 2

and

f(1) = 2*3¹ = 6

Points (0, 2) and (1, 6) are correct on the image 1 with blue graph

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3 years ago

Please simplify this equation

tester [92]

The answer would be x-8/x+3, thus option C.

6 0

3 years ago

Read 2 more answers

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

3 years ago