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3 years ago

f a 42.9 ft. flagpole casts a 253.1 ft. long shadow then how long is the shadow that a 6.2ft. tall woman casts

1 answer:

4 0

Here, Ratio of shadow to object = 253.1 / 42.9
So, it would remain constant for all objects.
Let, the show of women = x
Then, x / 6.2 = 253.1 / 42.9
x = 253.1 * 6.2 / 42.9
x = 36.58 Ft

In short, Your Answer would be 36.58 Feet

Hope this helps!

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The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x

RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

P(a < X < b) = $\int_{a}^{b} \frac{2}{x^{3}} dx$ = $2\int_{a}^{b} x^{-3} dx$

= $2[ \frac{x^{-3+1} }{-3+1}]^{b}_a dx$ { Because $\int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a$ }

= $2[ \frac{x^{-2} }{-2}]^{b}_a$ = $\frac{2}{-2} [ x^{-2} ]^{b}_a$

= $-1 [ b^{-2} - a^{-2} ]$ = $\frac{1}{a^{2} } - \frac{1}{b^{2} }$

a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }

Comparing with general probability we get,

P(1 < X < 5) = $\frac{1}{1^{2} } - \frac{1}{5^{2} }$ = $1 - \frac{1}{25}$ = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/ $8^{2}$ - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = $\frac{1}{6^{2} } - \frac{1}{10^{2} }$ = $\frac{1}{36} - \frac{1}{100 }$ = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

= $(\frac{1}{1^{2} } - \frac{1}{6^{2} })$ + (1/ $10^{2}$ - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

⇒ P(1 < X < x) = 0.75

⇒ $\frac{1}{1^{2} } - \frac{1}{x^{2} }$ = 0.75

⇒ $\frac{1} {x^{2} }$ = 1 - 0.75 = 0.25

⇒ $x^{2}$ = $\frac{1}{0.25}$ ⇒ $x^{2}$ = 4 ⇒ x = $2$

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0

3 years ago

125 tickets were sold for the jazz band concert for a total of $1,022. Students tickets cost $6 each, and general admission tick

rodikova [14]

Answer:

Number of student tickets sold are 57 and general tickets sold are 68.

Step-by-step explanation:

Let the number of student tickets = x and the number of general tickets = y.

It is given that in total 125 tickets were sold.

So, we have,

$x+y=125$

Also, students tickets is sold for $6 each and the general tickets are sold for $10 each.

Since, the total cost of the tickets is $1022.

So, we get,

$6x+10y=1022$

Thus, the system of equations obtained is,

x + y = 125 ........................(1)

6x + 10y = 1022

Multiply equation (1) by 6 gives us,

6x + 6y = 750 ............................(2)

6x + 10y = 1022 .........................(3)

Subtact (2) from (3), we get,

10y - 6y = 1022 - 750

i.e. 4y = 272

i.e. y= 68.

So, equation (1) gives,

x = 125 - y

i.e. y = 125 - 68

i.e. y = 57

Hence, the number of student tickets sold are 57 and general tickets sold are 68.

3 0

3 years ago

A juice pitcher holds 1.5 gallons of liquid. How many 8-ounce glasses of juice can be poured from a full pitcher? (1 gallon = 12

larisa86 [58]

$1gallon=128ounces\\To\ receive\ volume\ of\ pitcher\ in\ onces\ we\ need\ to\ multiply\ its\\volume\ in\ gallons\ by\ ounces\ in\ 1\ gallon.\\1,5g=1,5*128=192o\\Now\ to\ receive\ answer\ we\ need\ to\ divide\ volume\ of\ pitcher\ in\\ounces\ by\ volume\ of\ glass.\\192:8=24\\\\We\ need\ to\ 24\ glasses.$