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2 years ago

I need help with m-3 over 4 = m-3 over 5

Mathematics

1 answer:

MariettaO [177]2 years ago

6 0

M=3

You would begin by cross multiplying and then solving it from there:

5(m-3)=4(m-3)
5m-15=4m-12
5m-4m=-12+15
m=3

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Solve graphically, 2x^2+2x-4=0

alexandr402 [8]

The answer is in the picture below !

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3 years ago

A large company put out an advertisement in a magazine for a job

vova2212 [387]

Answer:

<em>C(19)=12 responses</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

The exponential function is frequently used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function can be expressed as follows:

$C(t)=C_o\cdot(1-r)^t$

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The company puts out an advertisement for a job opening. Initially, the company got 90 responses to the advertisement. Each day, the responses declined by 10%.

This is an example where the decay model can be used to calculate the responses to the advertisement at the day t.

The initial value is Co=90, the decaying rate is r=10% = 0.10. The model is written as:

$C(t)=90\cdot(1-0.1)^t$

Calculating:

$C(t)=90\cdot(0.9)^t$

We are required to calculate the number of responses at day t=19, thus:

$C(19)=90\cdot(0.9)^{19}$

C(19)=12 responses

8 0

2 years ago

9282737 + 1881 x 19916 =

sweet-ann [11.9K]

Answer to this math equation: 46744733

5 0

2 years ago

Read 2 more answers

To rent a boat, you pay for an initial fee plus. John rented a boat for 3 hours and paid $41. Jessica rented a boat for 6 hours

8090 [49]

Answer:

The intial fee is $5

The equation to represent this is: y=12x+5

12 is the cost per hour x=hours y=total cost

Step-by-step explanation:

77-41=36

36/3=12

12*6=72

77-72=5

6 0

3 years ago

PLEASE HELP!!!

AlekseyPX

Answer:

Step-by-step explanation:

Find the average rate of change of each given function over the interval [-2, 2]]:

✔️ Average rate of change of m(x) over [-2, 2]:

Average rate of change = $\frac{m(b) - m(a)}{b - a}$

Where,

a = -2, m(a) = -12

b = 2, m(b) = 4

Plug in the values into the equation

Average rate of change = $\frac{4 - (-12)}{2 - (-2)}$

= $\frac{16}{4}$

Average rate of change = 4

✔️ Average rate of change of n(x) over [-2, 2]:

Average rate of change = $\frac{n(b) - n(a)}{b - a}$

Where,

a = -2, n(a) = -6

b = 2, n(b) = 6

Plug in the values into the equation

Average rate of change = $\frac{6 - (-6)}{2 - (-2)}$

= $\frac{12}{4}$

Average rate of change = 3

✔️ Average rate of change of q(x) over [-2, 2]:

Average rate of change = $\frac{q(b) - q(a)}{b - a}$

Where,

a = -2, q(a) = -4

b = 2, q(b) = -12

Plug in the values into the equation

Average rate of change = $\frac{-12 - (-4)}{2 - (-2)}$

= $\frac{-8}{4}$

Average rate of change = -2

✔️ Average rate of change of p(x) over [-2, 2]:

Average rate of change = $\frac{p(b) - p(a)}{b - a}$

Where,

a = -2, p(a) = 12

b = 2, p(b) = -4

Plug in the values into the equation

Average rate of change = $\frac{-4 - 12}{2 - (-2)}$

= $\frac{-16}{4}$

Average rate of change = -4

The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]

3 0

2 years ago