The answer is C 2800 kg m/s
Given :
An 80kg sled rider starts sledding down a 100m hill from rest. If her final velocity is 15m/s.
To Find :
The acceleration down the hill.
The force needed for that kind of acceleration.
Solution :
By equation of motion :

Force required is, F = ma
F = 80×1.125 N
F = 90 N
Hence, this is the required solution.
<span>The ball clears by 11.79 meters
Let's first determine the horizontal and vertical velocities of the ball.
h = cos(50.0)*23.4 m/s = 0.642788 * 23.4 m/s = 15.04 m/s
v = sin(50.0)*23.4 m/s = 0.766044 * 23.4 m/s = 17.93 m/s
Now determine how many seconds it will take for the ball to get to the goal.
t = 36.0 m / 15.04 m/s = 2.394 s
The height the ball will be at time T is
h = vT - 1/2 A T^2
where
h = height of ball
v = initial vertical velocity
T = time
A = acceleration due to gravity
So plugging into the formula the known values
h = vT - 1/2 A T^2
h = 17.93 m/s * 2.394 s - 1/2 9.8 m/s^2 (2.394 s)^2
h = 42.92 m - 4.9 m/s^2 * 5.731 s^2
h = 42.92 m - 28.0819 m
h = 14.84 m
Since 14.84 m is well above the crossbar's height of 3.05 m, the ball clears. It clears by 14.84 - 3.05 = 11.79 m</span>
If I did my math right I believe 13 is the 9.3 seconds and 14 is the first option because of logic. The question basically says, how does the height change and the answer is the first one because it gets higher then lower, or increases then decreases.
A (max)= A (2pi/T)
a (max)= maximum acceleration
A= amplitude
T= periodic time
by definition, amplitude is the displacement from equillibrium point.
we see that maximum acceleration is directly proportional to the amplitude. so tripling the amplitude will triple the maximum acceleration.