Answer:
ωf = 8.8 rad/s
v = 2.2 m/s
Explanation:
We will use the third equation of motion to find the maximum angular velocity of the wheel:
![2\alpha \theta = \omega_f^2 -\omega_I^2](https://tex.z-dn.net/?f=2%5Calpha%20%5Ctheta%20%3D%20%5Comega_f%5E2%20-%5Comega_I%5E2)
where,
α = angular acceleration = 6 rad/s²
θ = angular displacemnt = 1 rev = 2π rad
ωf = max. final angular velocity = ?
ωi = initial angular velocity = 1.5 rad/s
Therefore,
![2(6\ rad/s^2)(2\pi\ rad)=\omega_f^2-(1.5\ rad/s)^2\\\omega_f^2=75.4\ rad/s^2+2.25\ rad/s^2\\\omega_f = \sqrt{77.65\ rad/s^2}](https://tex.z-dn.net/?f=2%286%5C%20rad%2Fs%5E2%29%282%5Cpi%5C%20rad%29%3D%5Comega_f%5E2-%281.5%5C%20rad%2Fs%29%5E2%5C%5C%5Comega_f%5E2%3D75.4%5C%20rad%2Fs%5E2%2B2.25%5C%20rad%2Fs%5E2%5C%5C%5Comega_f%20%3D%20%5Csqrt%7B77.65%5C%20rad%2Fs%5E2%7D)
<u>ωf = 8.8 rad/s</u>
Now, for linear velocity:
v = rω = (0.25 m)(8.8 rad/s)
<u>v = 2.2 m/s</u>
So, If the silica cyliner of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
To estimate the operating temperature of the radiant wall heater, we need to use the equation for power radiated by the radiant wall heater.
<h3>Power radiated by the radiant wall heater</h3>
The power radiated by the radiant wall heater is given by P = εσAT⁴ where
- ε = emissivity = 1 (since we are not given),
- σ = Stefan-Boltzmann constant = 6 × 10⁻⁸ W/m²-K⁴,
- A = surface area of cylindrical wall heater = 2πrh where
- r = radius of wall heater = 6 mm = 6 × 10⁻³ m and
- h = length of heater = 0.6 m, and
- T = temperature of heater
Since P = εσAT⁴
P = εσ(2πrh)T⁴
Making T subject of the formula, we have
<h3>Temperature of heater</h3>
T = ⁴√[P/εσ(2πrh)]
Since P = 1.5 kW = 1.5 × 10³ W
Substituting the values of the variables into the equation, we have
T = ⁴√[P/εσ(2πrh)]
T = ⁴√[1.5 × 10³ W/(1 × 6 × 10⁻⁸ W/m²-K⁴ × 2π × 6 × 10⁻³ m × 0.6 m)]
T = ⁴√[1.5 × 10³ W/(43.2π × 10⁻¹¹ W/K⁴)]
T = ⁴√[1.5 × 10³ W/135.72 × 10⁻¹¹ W/K⁴)]
T = ⁴√[0.01105 × 10¹⁴ K⁴)]
T = ⁴√[1.105 × 10¹² K⁴)]
T = 1.0253 × 10³ K
T = 1025.3 K
So, If the silica cylinder of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K
Learn more about temperature of radiant wall heater here:
brainly.com/question/14548124
The correct answer is low resistance.
A heating element's resistance is neither "extremely high" nor "very low." Since the amount of heat produced by the circuit is proportional to the current, the resistance of the heating element must be low enough to draw the necessary current. Thus, low resistance is the general characteristic of electrical devices like warmers, toasters, and heating pads. Any voltage will experience high current if resistance is too low. Current will be low if resistance is too high and voltage is okay. NOTE: Current increases as resistance decreases and decreases as resistance increases while the voltage remains constant, like in an automotive circuit.
Learn more about electrical appliances here :-
brainly.com/question/15081528
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<u>The force exerted by the person is an upward force equal to the weight of the box, and that force is perpendicular to the motion. If there is no motion in the direction of the force, then no work is done by that force. Yet you certainly feel like you are doing work if you carry a heavy box.</u>
- <u>In order to accomplish work on an object there must be a force exerted on the object and it must move in the direction of the force. Energy is required to do work and the basic SI unit of energy is the joule, the amount of energy required to exert a force of 1 Newton through a distance of 1 meter (1 joule = 1 newton meter).*picture 1*</u>
<u>For the special case of a constant force, the work may be calculated by multiplying the distance times the component of force which acts in the direction of motion.*picture 2*</u>
- <u>In order to accomplish work on an object there must be a force exerted on the object and it must move in the direction of the force.*picture 3*</u>
- <u>For a constant force F which moves an object in a straight line from x1 to x2 , the work done by the force can be visualized as the area enclosed under the force line below*picture 4*</u>
- <u>For the more general case of a variable force F(x) which is a function of x, the work is still the area under the force curve, and the work expression becomes an integral. *picture 5*</u>
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<u>credits-goo.gle,hyper physics </u>