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Black_prince [1.1K]
3 years ago
10

In 9 hours, a 170-lb person has drunk 4 16-oz beers

Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0
Ggghuudududjdgghbsdh
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Kaley and Tom both work at Publix as cashiers for $7.68 per hour. This week Kaley worked 5 more hours than Tom in overtime. Writ
natka813 [3]

Answer:

7.68h

38.4 + 7.68h

Step-by-step explanation:

Earnings per hour = $7.68

This week Kaley worked 5 more hours than Tom in overtime

h = number of hours Tom worked.

Tom's total earnings for the week = earnings per hour × number of hours

= $7.68 × h

= 7.68h

Tom's total earnings for the week = 7.68h

Kayley's total earnings for the week = earnings per hour × number of hours

He works 5 hours more than Tom in overtime.

Tom = h

Kayley = 5 + h

Kayley's total earnings for the week = earnings per hour × number of hours

= (7.68) × (5 + h)

= 38.4 + 7.68h

Kayley's total earnings for the week =

38.4 + 7.68h

8 0
2 years ago
Listen to internet sensation that's how im feeling atm..i really miss someone and he know's who he his :( sigh* pls come back..a
igomit [66]
Your answer would be -8.8472242e+14.


And... IF THAT SONG IS BY LIL DURK I LUV IT
3 0
3 years ago
Read 2 more answers
I need explanation and answer please,thanks.
Alla [95]
What’s the question?
3 0
3 years ago
I want to plant 45 sunflower plants and 81 rose plants in my garden. If I put the same number of plants in each row and each row
Minchanka [31]

Answer:

Rose plants has the greatest number of plants that can be put in one row that is 27

Step-by-step explanation:

If you wanted to plant 45 sunflowers and 81 rose plants in your garden you have to see which one has more and you get rose plants.all you have to do is subtract 1 from 81 and then put it with sunflowers.

3 0
3 years ago
Use the given information to find the exact value of the trigonometric function
eimsori [14]
\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}

Half Angle Formula

\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\  \\  \end{gathered}

Answer:

\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}

Checking:

\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{  (3rd quadrant)} \end{gathered}

Also,

\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}

The answer is none of the choices

7 0
1 year ago
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