Can 72/15 be simplified? Tell me what the number is in YOUR ANSWER. Please and thank you!

Plzzz help don’t understand plz explain

kherson [118]

So the easiest way to do this problem is to put your equation in linear form, meaning y = the rest of the equation.

I'm going to show the work to do that below:

2x - y = 4

-2x -2x (Here I am subtracting 2x)

- y = 4 - 2x

(-1)(- y) = (-1)(4 - 2x) (Now I'm multiplying both sides by -1 to make y positive)

y = 2x - 4 (And just for neat purposes I'm going to put the 2x in front of the 4)

Now you have your equation ( y=2x-4 ) and you're ready to put it on the points of your graph.

Start on the point (0, -4) to represent the y axis.

y = 2x - 4

Then, your rise (2) over your run (1)

so your coordinates for a line will be:

(0, -4) (-2, 1) (1, 0)

You only need to plot these three to connect your line.

I appologize for my lack of visuals i understand this might be confusing, however if you have any further questions feel free to let me know!

8 0

3 years ago

Jim drove 152 miles in 4 hours. if he can keep the same pace, how long will it take him to drive 760 miles?

alexandr402 [8]

First we need to find the rate which is the total amount driven divided by the total time.

152/4 = 38 miles per hour.

No we take the total driven miles given and divide it by the rate to find how long it would take!
760/38 = 20 hours!
Hope this helps :D

3 0

3 years ago

The third-degree Taylor polynomial about x = 0 of In(1 - x) is

gizmo_the_mogwai [7]

Answer:

$\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

MacLaurin/Taylor Polynomials

Approximating Transcendental and Elementary functions
MacLaurin Polynomial: $\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + ... + \frac{f^{(n)}(0)}{n!}x^n$
Taylor Polynomial: $\displaystyle P_n(x) = \frac{f(c)}{0!} + \frac{f'(c)}{1!}(x - c) + \frac{f''(c)}{2!}(x - c)^2 + \frac{f'''(c)}{3!}(x - c)^3 + ... + \frac{f^{(n)}(c)}{n!}(x - c)^n$

Step-by-step explanation:

*Note: I will not be showing the work for derivatives as it is relatively straightforward. If you request for me to show that portion, please leave a comment so I can add it. I will also not show work for elementary calculations.

Step 1: Define

Identify

f(x) = ln(1 - x)

Center: x = 0

n = 3

Step 2: Differentiate

[Function] 1st Derivative: $\displaystyle f'(x) = \frac{1}{x - 1}$
[Function] 2nd Derivative: $\displaystyle f''(x) = \frac{-1}{(x - 1)^2}$
[Function] 3rd Derivative: $\displaystyle f'''(x) = \frac{2}{(x - 1)^3}$

Step 3: Evaluate Functions

Substitute in center x [Function]: $\displaystyle f(0) = ln(1 - 0)$
Simplify: $\displaystyle f(0) = 0$
Substitute in center x [1st Derivative]: $\displaystyle f'(0) = \frac{1}{0 - 1}$
Simplify: $\displaystyle f'(0) = -1$
Substitute in center x [2nd Derivative]: $\displaystyle f''(0) = \frac{-1}{(0 - 1)^2}$
Simplify: $\displaystyle f''(0) = -1$
Substitute in center x [3rd Derivative]: $\displaystyle f'''(0) = \frac{2}{(0 - 1)^3}$
Simplify: $\displaystyle f'''(0) = -2$

Step 4: Write Taylor Polynomial

Substitute in derivative function values [MacLaurin Polynomial]: $\displaystyle P_3(x) = \frac{0}{0!} + \frac{-1}{1!}x + \frac{-1}{2!}x^2 + \frac{-2}{3!}x^3$
Simplify: $\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}$

Topic: AP Calculus BC (Calculus I/II)

Unit: Taylor Polynomials and Approximations

Book: College Calculus 10e

5 0

3 years ago

Can a fraction be a whole number

Aleonysh [2.5K]

Yes. 1/1 is a fraction but it can be simplified to 1 which is a whole number.

6 0

2 years ago

Naomi pays $1.50 each time she rides the city bus. She has already ridden the bus 18 times so far this year. The expression 1.50

Mashutka [201]

Answer:

D, 1.50(18)

Step-by-step explanation:

just guessing lol

4 0

2 years ago