Please !!! Someone help me
2 answers:
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Answer:
a)
b)
c)
Step-by-step explanation:
Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.
To find : The following probabilities by summing the probabilities of the appropriate sample points ?
Solution :
The sample space is
S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}
n(S)=8
A: At least one head is observed
i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}
n(A)=7
B: At least two heads are observed
i.e. B={HHH,HTT,TTH,THT}
n(B)=4
C: The number of heads observed is odd.
i.e. C={HHH,HTT,THT,TTH}
n(c)=4
a) Probability of A, P(A)
b) P(A or B)
Using formula,
(c) P((not A) or B or (not C))
A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}
not A = {TTT} = 1
B={HHH,HTT,TTH,THT}
C={HHH,HTT,THT,TTH}
not C = {HHT,HTH,THH,TTT} = 4
So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5
Answer:
The number of tickets must be sold is 2500
Step-by-step explanation:
The charge for each ticket = $ 5
The concessions amount = $ 1400
The amount paid to players = $ 2000
The amount paid to workers = $ 1600
The cost of each bag given to each fan = $ 3 per bag
Let The number of tickets sold = x
Now, number of ticket sold = number of fans = x
So, According to question
( charge per ticket × number of fans - cost of each bag × number of fan - concession amount ) = amount paid to players + amount paid to workers
Or, $5 x - $3 x - $1400 = $2000 + $1600
Or, $2 x = $3600 + $1400
Or, $2 x = $5000
∴ x = = 2500
Hence Answer