To negatives equal a positive. Convert both of the mixed numbers into a improper fraction. Cross simplify 5 and 5, they both turn into one’s. Multiply and you should get 7/3 or 2 1/3.

7 0

3 years ago

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Is 26,341 divisible by 3?

shepuryov [24]

No. 26,341 is not evenly divisible by 3 .

Here's the trick you can use to decide this
just by looking at a big number:

==> If a number is divisible by 3, then the
sum of its digits is divisible by 3.

I've never taken the trouble to figure out why this works,
but it does work. I didn't make it up. It's widely known.

So let's look at 26,341 .

The sum of the digits is (2 + 6 + 3 + 4 + 1) = 16 .

16 is not divisible by 3 , so 26,341 is not divisible by 3 .

Is that cool or what !

3 0

3 years ago

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Pls help pls pls ): precalc

Lena [83]

<h3>Answer: Choice A</h3>

$\log_p N = b$ is not the same as $b^p = N$

The base of the log is p, while the base of the exponential is b. The two don't match. If it said $\log_p N = b \text{ is the same as } p^b = N$ then it would be a valid statement since the bases are both p.