Answer:
Ss and ss
Explanation:
<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>
<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>
Now, let us look at a cross between the two parents;
Ss x ss
Progeny: Ss, Ss, ss, ss.
Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.
Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.
Hence, the genotypes of the two parents are Ss and ss.
That's false, it's the pons :)
Answer:
The correct order would be
- Glucose
- ATP→ADP
- H₂O
- Pyruvate
- CO₂
Explanation:
Following reactions occur in Glycolysis and Kreb's Cycle
- Phosphorylation of Glucose- In the first step of glycolysis, Glucose is converted into Glucose-6-Phosphate using 1 ATP molecule by Hexokinase enzyme. One phosphate group from ATP is attached to glucose by the enzyme, thus forming ADP.
- Dehydration- In the ninth step of Glycolysis, each of two molecules of 2-Phosphoglycerate are converted to Phosphoenol Pyruvate, by Enolase enzyme, releasing two H₂O molecules.
- Formation of Pyruvate- In the last or tenth step of Glycolysis, each of two molecules of Phosphoenol Pyruvate are converted to Pyrutave using an ATP by the enzyme Pyruvate Kinase.
- Oxidation Of Pyruvate to Acetyl-CoA- Before the Kreb's Cycle starts, the Pyruvate molecule obtained from the Glycolysis undergoes oxidative decarboxylation producing Acetyl-CoA and release of CO₂ and NADH.
Answer:
A fire will burn all of its potential energy while cellular respiratory will store it as ATP
also
burning a fire releases all of the energy in the fuel as heat and light.
Hope this Helps
