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Marysya12 [62]
3 years ago
10

What is the answer to 3(5)​

Mathematics
2 answers:
elixir [45]3 years ago
6 0
The answer is gonna be 15
zmey [24]3 years ago
4 0

Answer: 15

Step-by-step explanation:

3x5=15

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20.49 maybe?

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11) 54% of 35 is what?
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18.36

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Rationalize <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%20%5Csqrt%7B7%7D%20%2B%203%20%5Csqrt%7B3%7D%20%20%7D%20"
Ivahew [28]
\dfrac{1}{2 \sqrt{7} + 3 \sqrt{3}  }

= \dfrac{1}{2 \sqrt{7} + 3 \sqrt{3} } \times  \dfrac{2 \sqrt{7} - 3 \sqrt{3}}{2 \sqrt{7} - 3 \sqrt{3}}

=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{(2\sqrt{7})^2 - (3\sqrt{3})^2}

=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{28 - 27}

=\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{1}

=2 \sqrt{7} - 3 \sqrt{3}

6 0
4 years ago
Roger can run one mile in 18 minutes. jeff can run one mile in 15 minutes. if jeff gives roger a 1 minute head start, how long w
gladu [14]

Alright, lets get started.

Roger can run one mile in 18 minutes.

Jeff can run one mile in 15 minutes.

Suppose in x minutes, they both will catch up.

Roger runs in 18 minutes = 1 mile

So, Roger will run in 1 minute = \frac{1}{18} miles

So, Roger will run in x minutes = \frac{x}{18} miles

Jeff runs in 15 minues = 1 mile

So, Jeff will run in 1 minute = \frac{1}{15} mile

As Jeff gives roger a 1 minute head start, means Jeff will have x-1 minute time to run

So, Jeff will run in (x-1) minute = \frac{x-1}{15}

As both are cathing up means they both runs same distance, means

\frac{x}{18} =\frac{x-1}{15}

Cross Multiplying

15 x = 18x - 18

3 x = 18

x = 6 minutes

So for calculating distance = speed * time

Distance = \frac{1}{18} *6 = \frac{1}{3} miles

It means it will take 1/3 or 0.33 miles before jeff catches up to roger.   :   Answer

Hope it will help :)



4 0
3 years ago
The temperature is 8°F. It is expected to fall at 5° each hour for the next several hours. In how many hours will the temperatur
Natalija [7]

Answer:3 hours

Step-by-step explanation:8-5=3, 3-5=-2, -2-5=-7

7 0
3 years ago
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