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4 years ago

I need your helpppppppppp

Mathematics

1 answer:

viva [34]4 years ago

3 0

Answer:

For A: 4 tens and 6 ones

For b: same as A 4 tens and 6 ones

for C: 46 cents

Step-by-step explanation:

dimes is tens and pennies are one each

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If malik has 4 times as many nickels as quarters and they have a combined value of 225 cents, how many of each coin does he have

mafiozo [28]

Take 4 multiply by 10 then divide 225 by 40

4 0

3 years ago

Help with this pls.

Phoenix [80]

Answer:

20 = AC

Step-by-step explanation:

AB+BC = AC

11+9 = AC

20 = AC

6 0

4 years ago

LOTS OF POINTS PLEASE HELPPPP

Ivanshal [37]

Answer: -2(5) over -1(6)

Step-by-step explanation:

1. X^2 - 3x - 10

X + 2 = 0 ⇒ −2

X1 = X − 5 = 0 ⇒ X2 = 5

2. X^2 - 5x - 6

X + 1 = 0 ⇒ X1 = −1

X − 6 = 0 ⇒ X2 = 6

3 0

4 years ago

Read 2 more answers

Assuming the probability of a single sample testing positive is 0.15, find the probability of a positive result for two samples

Grace [21]

Answer:

$P(Positive\ Mixture) = 0.2775$

The probability is not low

Step-by-step explanation:

Given

$P(Single\ Positive) = 0.15$

$n = 2$

Required

$P(Positive\ Mixture)$

First, we calculate the probability of single negative using the complement rule

$P(Single\ Negative) = 1 - P(Single\ Positive)$

$P(Single\ Negative) = 1 - 0.15$

$P(Single\ Negative) = 0.85$

$P(Positive\ Mixture)$ is calculated using:

$P(Positive\ Mixture) = 1 - P(All\ Negative)$ ---- i.e. complement rule

So, we have:

$P(Positive\ Mixture) = 1 - 0.85^2$

$P(Positive\ Mixture) = 1 - 0.7225$

$P(Positive\ Mixture) = 0.2775$

<em>Probabilities less than 0.05 are considered low.</em>

<em>So, we can consider that the probability is not low because 0.2775 > 0.05</em>

6 0

3 years ago

If he is correct, what is the probability that the mean of a sample of 68 computers would differ from the population mean by les

elena-14-01-66 [18.8K]

Complete Question

The quality control manager at a computer manufacturing company believes that the mean life of a computer is 91 months with a standard deviation of 10 months if he is correct. what is the probability that the mean of a sample of 68 computers would differ from the population mean by less than 2.08 months? Round your answer to four decimal places. Answer How to enter your answer Tables Keypad

Answer:

$P(-1.72$