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2 years ago

6

Greatest common factor of the following monomials 34c^3 and 2c^5

1 answer:

melamori03 [73]2 years ago

4 0

This would be 2c^3 Answer

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Use words and math to explain why these two expressions are equivalent.

Sunny_sXe [5.5K]

Answer:

here

Step-by-step explanation:

when given the first set, you combine like terms so you add 5h and 3h together and -6 and 2 are combined, so the first one is 8h -4. The second set you distribute 2 to 4h and -2 getting you 8h and -4 as well

5 0

2 years ago

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At summer camp the ratio of boy to girls was 7:1. If there were 63 boys, how many girls were there

solmaris [256]

For every 7 boys, there is one girl

So: 63/7 = 9

There are 9 girls.

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3 years ago

Read 2 more answers

Solve the following equation in terms of x.<br><br> 20x - 3y = z

Lostsunrise [7]

Step-by-step explanation:

I think Rewrite the equation as

z

=

20

x

−

3

y

.

z

=

20

x

−

3

y

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2 years ago

Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

3 years ago

On the set of axes below, triangle ABC is graphed. Triangles A'B'C'

Nezavi [6.7K]

Answer:

Step-by-step explanation:

a reflection followed by a rotation

5 0

2 years ago