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soldi70 [24.7K]
2 years ago
9

On march 12, klein company, inc. sold merchandise in the amount of $7,800 to babson company, with credit terms of 2/10, n/30. th

e cost of the items sold is $4,500. klein uses the perpetual inventory system. on march 15, babson returns some of the merchandise. the selling price of the merchandise is $600 and the cost of the merchandise returned is $350. babson pays the invoice on march 20, and takes the appropriate discount. the amount that klein receives from babson on march 20 is: $7,800. $7,644. $7,044. $7,056. $7,200.
Mathematics
1 answer:
Assoli18 [71]2 years ago
6 0
Given:
<span>march 12 - Klein company, inc. sold merchandise in the amount of $7,800 to Babson company, with credit terms of 2/10, n/30
</span><span>march 15 - Babson returns some of the merchandise. the selling price of the merchandise is $600
march 20 - Babson pays the invoice and takes the appropriate discount.

Since March 20 is still within the 10-day discount from date of purchase, Babson is entitled to 2% discount.

7,800 - 600 = 7,200 sales invoice
7,200 * 2% = 144 sales discount
7,200 - 144 = 7,056 net sales

Babson will pay the amount of $7,056</span>
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Can someone please help me with this question?
liq [111]
To get the solution we are looking for we need to point out what we know.
1. We assume that 55 is 100% because its the output value of the task.
2. We assume that the x is the value we are looking for. 
3. If 100% = 55 so we can write it down as 100%=55 
4. We know that x% = 44 of the output value so we can write it as x%=44.
5. Now we have two simple equations: 1) 100%=55 2) x%=44 where left sides of both of them have the same units and both right sides have the same units so we can do something like that 100%/x%=55/44.
6. Now we just have to solve the simple equation and we will get the answer.
7. Solution for 44 is what percent of 55 100%/x%=55/44 (100/x)*x=(55/44)*x we multiply both sides of the equation by x 100= 1.25*x we divide both sides of the equation by (1.25) to get x 100/1.25=x 80=x now we have: 44 is 80% of 55! 

Quick answer = 44 is 80% of 55
Hope this helps! ;D
3 0
3 years ago
A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute
nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

P(k\geq8)=1-P(k

P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\

P(k

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002

5 0
3 years ago
Simplify equations HELP NOW!!
Anna [14]

Answer:

\frac{1}{5} (2x+10)=4 x=5

\frac{1}{3} (3x+9)=9 x=6

Step-by-step explanation:

\frac{1}{5} (2x+10)=4

Multiply both sides of the equation by 5.

5 · \frac{1}{5} · (2x+10)= 5 · 4

Simplify both sides of the equation.

2x+10=20

Subtract 10 from both sides of the equation.

2x=10

Divide each term by 2 and simplify.

x=5

--------------------------------------------------------------------

\frac{1}{3} (3x+9)=9

Substitute x for 6

\frac{1}{3} (3(6)+9)=9

Multiply 3 · 6

\frac{1}{3} ((18)+9)=9

Add 18 + 9

\frac{1}{3} (27)=9

Divide \frac{1}{3} ÷ 27

9 = 9

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Step-by-step explanation:

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2 years ago
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