Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
option D. 4.7 x 10-4 m
Step-by-step explanation:
<u><em>The correct question is</em></u>
• cell P: 5.0 x 10-4 meters
• cell Q: 3.0 x 10-5 meters
we have
The diameter of cell P is 
The diameter of cell Q is 
Rewrite the diameter of cell P as

Find the difference

Rewrite the difference as

Answer:
[See Below]
Step-by-step explanation:
❶ It is irrational because to make it repeating it must be <u>EXACT</u>. In this case it is adding a 0 after every 1. So it'd be irrational since it doesn't have an end.
❷ Irrational because no one knows the end of pi. It doesn't have an ending so therefore irrational.
~<em>Hope this helps Mate. If you need anything feel free to message me. </em>
The slope of the trail would be 18. hope it helps
That's the Kolakovski sequence,