Each of those bones pictures are equal to 2 bones. The question is asking, how many more rib bones than skull and jaw bones combined, so you’re gonna have to do some addition and subtraction.
You take the number of skull bones, which is 1(2), and add that to the number of jaw bones, which is 0. Giving you a total of 2 bones.
Then you are taking the rib bones 3(2) and finding out that you have 6.
So with that information, you can find out that there are 4 more rib more than skull and jaw bones combines (6-2=4)
SOLUTION
Given B is the midpoint of AC ABBC 1 and C is the midpoint of BD BCCD2 ie on adding 1 and 2 ART We get ABBCBCCD hence ABCD hence proved
II(RS is a median) and III(RS is a side of RST)
Answer:true
Explanation:
24+24=48
48-8=40
40x2=80
80=80!
So it is true.
14 ribbons.
7 divided by 1/2 is 14. dividing by a fraction or decimal is just like multiplying without the decimal point or numerator.
