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sveta [45]
3 years ago
14

What is an equation of the line that passes through the points (−5,6) and (7, 6)

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

y = 6

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-5, 6) and (7, 6). Substitute:

m=\dfrac{6-6}{7-(-5)}=\dfrac{0}{12}=0

The slope m = 0. Therefore it's a horizontal line y = a.

In the given points we have y = 6.

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What is the slope of the line that passes through the points (-2, -5) and (6, 7)? A.3/2 B.2/3 C.-3/2 D.-2/3
Fynjy0 [20]

Answer:

3/2

Step-by-step explanation:

y2 - y1/ x2 - x1

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12/ 8

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8 0
3 years ago
p is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin o to p is a minimum. find the
REY [17]
Coolio

alright, so the disatnce formula is
D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

solve for y in the equation given on top
2x+y-10=0
y=10-2x
ok
so (x1,y1)=(0,0), the first point
(x2,y2)=(x,10-2x)
so subsitute to get

D=\sqrt{(x-0)^2+(10-2x-0)^2}
D=\sqrt{(x)^2+(10-2x)^2}
D=\sqrt{x^2+4x^2-40x+100}
D=\sqrt{5x^2-40x+100}
find the miniumum
we only need to minimize what is under the square root so
take the derivitive of 5x²-40x+100
that is 10x-40
it is 0 at x=4
when x<4, the derivitive is negative
when x>4, the derivitive is positve
goes from negative to positive
so it is a minimum

at x=4
find y
y=10-2x
y=10-2(4)
y=10-8
y=2

(4,2)
find min distance

D=\sqrt{(x-0)^2+(y-0)^2}
D=\sqrt{(4-0)^2+(2-0)^2}
D=\sqrt{(4)^2+(2)^2}
D=\sqrt{16+4}
D=\sqrt{20}
D=2\sqrt{5}



the point, P, is (4,2) and the minimum distance is 2√5
5 0
4 years ago
What’s is the same as 97.52 divided by 10
Tems11 [23]
You could do 97.52/10. The slash means divided by.
6 0
3 years ago
Round to the nearest hundredth
r-ruslan [8.4K]
The answer would be 43.98 2^2 •3.5=43.9823
4 0
3 years ago
Read 2 more answers
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