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alexandr1967 [171]
4 years ago
13

Select the best attribute for the angle pair formed by two parallel lines intersected

Mathematics
1 answer:
Inga [223]4 years ago
7 0

Answer:

Corresponding Angles sum to 180°

Step-by-step explanation:

If a pair of parallel lines is cut by transversal that is not perpendicular to the parallel lines as shwon in the figures (attached below), then;

Four angles are acute, and four are obtuse.

  • All four acute angles are equal: 2=3=6=7
  • All four obtuse angles are equal: 1=4=5=8
  • The sum of acute and obtuse angles is 180:                                          for example, 1+2=180, 3+4=180, 5+6=180, 7+8=180

so the best attribute for the angle pair formed by two parallel lines intersected  by a transversal is that Corresponding Angles sum to 180°.

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Gas is escaping from a spherical balloon at the rate of 12 ft3/hr. At what rate (in feet per hour) is the radius of the balloon
bija089 [108]

Answer:

This is the rate at which the radius of the balloon is changing when the volume is 300 ft^3 \frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \:\frac{ft}{h}  \approx -0.05537 \:\frac{ft}{h}

Step-by-step explanation:

Let r be the radius and V the volume.

We know that the gas is escaping from a spherical balloon at the rate of \frac{dV}{dt}=-12\:\frac{ft^3}{h} because the volume is decreasing, and we want to find \frac{dr}{dt}

The two variables are related by the equation

V=\frac{4}{3}\pi r^3

taking the derivative of the equation, we get

\frac{d}{dt}V=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4}{3}\pi (3r^2)\frac{dr}{dt} \\\\\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}

With the help of the formula for the volume of a sphere and the information given, we find r  

V=\frac{4}{3}\pi r^3\\\\300=\frac{4}{3}\pi r^3\\\\r^3=\frac{225}{\pi }\\\\r=\sqrt[3]{\frac{225}{\pi }}

Substitute the values we know and solve for \frac{dr}{dt}

\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}\\\\\frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2} \\\\\frac{dr}{dt}=-\frac{12}{4\pi (\sqrt[3]{\frac{225}{\pi }})^2} \\\\\frac{dr}{dt}=-\frac{3}{\pi \left(\sqrt[3]{\frac{225}{\pi }}\right)^2}\\\\\frac{dr}{dt}=-\frac{3}{\pi \frac{225^{\frac{2}{3}}}{\pi ^{\frac{2}{3}}}}\\\\\frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \approx -0.05537 \:\frac{ft}{h}

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You have to be very careful how you set this up. For every girl (who counts as 1) there are 3 boys (who count as 3). The total number in the proportion is 3 + 1 =4. You are given a total, but that is both boys and girls. That's why you need the 4.

3/4 = x / 236 Cross multiply

4x = 3 * 236

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Answer:

2(x + 3) <9

Step-by-step explanation:

<u>Two times</u> the <em>quantity of a number increased by 3</em> is <u>less than 9</u>

       2  ·                                          (x + 3   )                           < 9    

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