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3 years ago

Standard form of line that passes thru (-3,5) and (-2,-6)

Mathematics

1 answer:

katovenus [111]3 years ago

4 0

Answer:

11x + y = -28

Step-by-step explanation:

Step 1: Find slope

(6-5)/(-2--3) = -11

Step 2: Find y-intercept

y = -11x + b

5 = -11(-3) + b

5 = 33 + b

b = -28

Step 3: Write in slope-intercept form

y = -11x - 28

Step 4: Convert to standard form

11x + y = 28

And we have our final answer!

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Brrunno [24]

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2 years ago

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3 years ago

WILL GIVE BRAINLIEST, THANKS, AND 5 STARS! PLEASE HELP ME!

Bogdan [553]

Answer:

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Step-by-step explanation:

Method 1

Apply Difference of Two Squares Formula: $a^2-b^2=(a+b)(a-b)$

Given $x^2-16=0$

Rewrite 16 as 4²

Therefore, $a^2=x^2$ and $b^2=4^2$

$\implies a = \sqrt{x^2}=x$

$\implies b=\sqrt{4^2} =4$

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$\implies (x+4)(x-4)=0$

$\implies (x+4)=0 \implies x=-4$

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Method 2

Given equation:

$x^2-16=0$

Add 16 to both sides:

$\implies x^2-16+16=0 + 16$

$\implies x^2=16$

Square root both sides:

$\implies \sqrt{x^2}=\sqrt{16}$

$\implies x=\pm4$

Therefore, x = -4, x = 4

6 0

2 years ago

If the interest rate is 10% a month what is the annual rate? 213.8?

Hatshy [7]

On month -------- 10%
12 month ---------- x %
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3 years ago