Answer:
(x+2) (x+3) (x-5)
Step-by-step explanation:
x³-19x-30 = (x+2) (x²+ax-15) ... x³=x*(1*x²) while -30= (2)*(-15)
x³ +<u> 0</u>*x² - 19x -30 = x³ + (<u>2+a</u>)x² + (2a-15)x -30
2+a = 0
a = -2
x³-19x-30 = (x+2) (x²-2x-15) = (x+2) (x+3) (x-5)
The tangent of an angle is the ratio of the opposite side to the adjacent side.
... tan(45°) = (height above eye level)/(20 m)
... height above eye level = (20 m)·tan(45°) = (20 m)·1 = 20 m
_____
Eye level is 1.7 m above ground, so the height of the flagpole above ground is
... height of pole = height above eye level + height of eye level
... height of pole = 20 m + 1.7 m = 21.7 m
Answer:
m>14 or m< -2
Step-by-step explanation:
A. Reflection across x. Left shift 2.
b. Right shift 3, up 6
c. Up 1
d. Reflect across x, right 5, down 2.
e. Down 4, vertical stretch 3.
f. Right 2, up 5, compression 2/5
g. Left 5
h. Reflect x down 4
To solve for c, you need to get c onto one side of the equation, or make it c=__. So what I would do first is subtract a/b from both sides
a/b + c = d/c
-a/b
a/b - a/b + c = d/c - a/b
c = d/c-a/b