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Igoryamba
3 years ago
11

Evaluate 66 - 20 - 32 1/4

Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Answer:

13.75

Step-by-step explanation:

66-20- 32 1/4

66-20- 32.25

46-32.25

13.75

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Pls brainlest ASAP and add extra points for correct answer
vlabodo [156]

Answer:

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water and carbon dioxide on the right (they go out of the cell)

3 0
3 years ago
A statistician calculates that 8% of Americans own a Rolls Royce. If the statistician is right, what is the probability that the
hichkok12 [17]

Answer:

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

A statistician calculates that 8% of Americans own a Rolls Royce.

This means that p = 0.08

Sample of 595:

This means that n = 595

Mean and standard deviation:

\mu = p = 0.08

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.08*0.92}{595}} = 0.0111

What is the probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%?

Proportion above 8% + 3% = 11% or below 8% - 3% = 5%. Since the normal distribution is symmetric, these probabilities are equal, and so we find one of them and multiply by 2.

Probability the proportion is less than 5%:

P-value of Z when X = 0.05. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.05 - 0.08}{0.0111}

Z = -2.7

Z = -2.7 has a p-value of 0.0035

2*0.0035 = 0.0070

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

8 0
3 years ago
What is the geometric sequence?<br><br> 2,3,4.5?
kykrilka [37]
An=a12n-1 or an=(1)2n-1
7 0
3 years ago
I have the formula <br><br> A fraction • π r^2
MatroZZZ [7]

Answer:

22.2 ft²

Step-by-step explanation:

The area (A) of a sector is calculated as

A = area of circle × fraction of circle

  = πr² × \frac{50}{360}

  = π × 7.13² × \frac{5}{36}

  = \frac{7.13^2(5)\pi }{36} ≈ 22.2 ft² ( nearest tenth )

4 0
4 years ago
- Paul wants to figure out the fuel consumption of his new SUV in the city. He made
Vesnalui [34]

Answer:

a.15.1 L/100 km; b $72.75; c. $51.34

Step-by-step explanation:

(a) Fuel consumption

Fuel used = 75 L

Distance travelled = 6096 km - 5600 km = 496 km

\text{Fuel consumption} = \dfrac{\text{75 L}}{\text{496 km}}  \times \dfrac{\text{ 100 km}}{\text{100 km}} = \dfrac{\text{15.1 L}}{\text{100 km}}

(b) Cost to fill tank

\text{Cost} = \text{75 L} \times \dfrac{\text{\$0.97}}{\text{1 L}} = \$72.75

(c) Cost per week

i. Calculate the volume of gasoline

\text{Volume} = \text{350 km} \times \dfrac{\text{75 L}}{\text{496 km}} = \text{52.9 L}

ii. Calculate its cost

\text{Cost} = \text{52.9 L} \times \dfrac{\text{\$0.97}}{\text{1 L}} = \$51.34

8 0
3 years ago
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