I forgot my trig but I can see if I can do something
this will be a confusing solution
if we figure out the 3rd angle, it is 55
therefor we has a sideways isocoleese triangle (see attachment)
we can draw an auxilary (imaginary) line from left tower to left side to make 2 identical right triangles with hypotonuse 5 and the angles are 35 and 55
erase all that, and now we have
draw an immaginary line (see attachmen 2) from bottom to top to represent height
I am going to try to find the base (leg)
cos=a/h
cos(70°)=x/5
times both sides by 5
5cos(70°)=x (from left tower to perpendicular line)
now
a²+b²=c²
(5cos(70°)²+h²=5²
25(cos(70°))²+h²=25
minus 25(cos(70°))² both sides
h²=25-25(cos(70°))²
h²=25(1-(cos(70°)²))
square root both sides
h=5√(1-(cos(70°)²)) or 5cos(pi/9)
evaluate with your calculator
h=4.6984km
round
h=4.7km
Answer:
Step-by-step explanation:
If we make 80% of our foul shot,
% means out of 100
80/100
8/10
4/5
These all represent the same fraction
Answer:2
Step-by-step explanation:because table 1 is a negative and that is not a function
Answer:
Step-by-step explanation:
144
6×4=24
24×6=144
(no idea what to type for 20ccharavters long.)