2y-x=3/4(-y+1)first distribute
2y-x=-3/4y+3/4 get the y on one side
2y-x+3/4y=3/4 add 3/4y to both sides
2y+3/4y=3/4+x add x to both sides
11/4y=3/4+x now divide by 11/4 (both sides)
y=3/11+4/11x
y=3+4x/11
choice c is the answer
Answer:
503 $1 tickets sold.
Step-by-step explanation:
Use two equations
Let x = number of $1 tickets sold
Let y = number of $1.50 tickets sold
x + y = 739
1x + (1.5)y = 857
First equation ==> y = 739 - x
Plug this into the second equation
x + (1.5)(739 - x) = 857
x + 1108.5 - 1.5x = 857
- 0.5x = -251.5
x = 503
There were 503 $1 tickets sold.
To find the number of $1.50 tickets, just plug this value of x into either one of the equations.
(503) + y = 739 (739 - 503 = 236)
y = 236
There were 236 $1.50 tickets sold.
False, you graph an open circle on -3 and shade to the right because x must be larger than -3 and it can not equal -3
we know that
The scalar magnitude of the velocity vector is the speed. The speed is equal to
in this problem we have
substitute in the formula
therefore
<u>the answer Part a) is</u>
the speed is equal to 
<u>Part b) </u>Find the velocity
we know that
<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it
in this problem we have
the magnitude is equal to the speed
therefore
<u>the answer Part b) is</u>
the velocity is 
Part c)
we know that
the acceleration is equal to the formula
in this problem we have
substitute in the formula
therefore
<u>the answer Part c) is</u>
the acceleration is 
This is an example of negative acceleration
Answer:
Step-by-step explanation:
The answer is 18794.86549
