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muminat
3 years ago
9

What is the rational exponent expression of 6 square root of f

Mathematics
1 answer:
Nutka1998 [239]3 years ago
3 0
6(f)^0.5
is this what you meant?

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Quadrilateral ABCD is rotated 270° clockwise about the origin. What are the
nirvana33 [79]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
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If w = 6 units, x = 3 units, and y = 5 units, what is the surface area of the figure?
Dima020 [189]

*see attachment for the diagram

Answer:

A. 178 units²

Step-by-step explanation:

Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)

✔️Surface area of the square pyramid = s² + 2*s*l

Where,

s = side length of square base (w) = 6 units

l = slant height = ?

Use Pythagorean theorem to find l

l = √((w/2)² + y²)

l = √((6/2)² + 5²) = √(9 + 25)

l = √34

l ≈ 5.8 units

Surface area of the square pyramid = 6² + 2*6*5.8 = 105.6 units²

✔️Surface area of square prism:

SA = 2a² + 4ah

Where,

a = w = 6 units

h = x = 3 units

Substitute

SA = 2(6²) + 4*6*3

= 72 + 72

= 144 units²

✔️base area of the square pyramid = s²

s = w

Base area = 6²

Base area = 36 units²

✅Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)

Surface area of the figure = (105.6 + 144) - 2(36)

= 249.6 - 72

= 177.6

≈ 178 units²

7 0
3 years ago
A point P lies on the line with equation y= 4-3X. The point P is a distance √34 from the origin. Find the two possible positions
Oksi-84 [34.3K]

The two possible positions of point P are:

(3, -5) and (0.6, 5.8)

<h3>How to find the two possible positions of point P?</h3>

We know that point P lies on the line:

y = 4 - 3*x

And that the distance between P and the origin is √34, then if the coordinates of point P are (x, y), we have that:

\sqrt{34} = \sqrt{x^2 + y^2}

Now, we can replace "y" in the distance equation by the linear equation, and also remove the square roots:

34 = x^2 + (4 - 3x)^2

Now we can solve the quadratic equation for x:

34 = x^2 + 9x^2 + 16 - 24x\\\\10x^2 - 24x - 18 = 0\\\\

The solutions are:

x = \frac{24 \pm \sqrt{(-24)^2 - 4*10*(-18)} }{2*10} \\\\x = \frac{24 \pm36}{20}

So the two solutions are:

x = (24 + 36)/20 = 3

x = (24 - 36)/20 = -0.6

To get the points, we need to evaluate y on these values:

y = 4 - 3*3 = -5   So we have P = (3, -5)

y = 4 - 3*(-0.6) = 2.2 So we have the point (0.6, 5.8)

There are the two possible positions of point P.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

5 0
2 years ago
Y= -3x+5 please solve
pychu [463]
X can be from -1.6 to -1.7 or x can be from -3.3 to 3.3
6 0
3 years ago
Read 2 more answers
-2+{-3}=<br> Helpppp meeee
kondor19780726 [428]

Answer:

-5 should be the answer

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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