Addition
~Hope that helped!~
~Izzy <3~
I think you meant to say

(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

Answer:
The answer is 8
Step-by-step explanation:
12*10=120 120/15=8
Answer:
0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 17.39 ppm
Standard Deviation, σ = 4.25 ppm
Sample size = 11
We are given that the distribution of printing speed is a bell shaped distribution that is a normal distribution.
Formula:
P(printing speed of the sample is greater than 17.99 ppm.)
P(x > 17.99)

Calculating the value from the standard normal table we have,

Thus, 0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.