Answer:
5000(1+0.41)^5
Step-by-step explanation:
Growth at a rate of 41% means the number of transistors keeps its 100%, and adds 41%, percent more. So each year, the number is multiplied by 100% + 41%, which is the same as a factor of (1+0.41).
After 0 years (i.e., in 1974), the number of transistors in a dense integrated circuit was 5000.
After 1 year, that number was multiplied by 1 + 0.41, so it was 5000(1+0.41)
After 2 years, the number was again multiplied by 1+0.41, so 5000⋅(1+0.41)⋅(1+0.41) , which is 5000(1+0.41)^2
We can keep doing this until we get to 5 years after 1974, which is 1979.
In conclusion, this is an expression for the number of transistors in a dense integrated circuit in 1979:
5000(1+0.41)^5
