Yo sup??
m3 and m6 for a supplementary pair therefore
m3+m6=180
122+m6=180
m6=58
Hope this helps
Answer:
100 dollars a month I think
Answer:
p=4x^3−3x^2+5x−2/x
Step-by-step explanation:
Let's solve for p.
px=4x^3−3x^2+5x−2
Step 1: Divide both sides by x.
px/x=4x^3−3x^2+5x−2/x
p=4x^3−3x^2+5x−2/x
Answer:
p=4x^3−3x^2+5x−2/x
( I hope this was helpful) >;D
Option B
We can store a total of 360 songs in 60 megabytes of space.
<u>Solution:</u>
It is given to us that It takes 24 megabytes to store 144 songs on a music player. We have been asked to find out what is the greatest number of songs that 60 megabytes could store.
To solve this question we can use the unitary method.
We will first find out how many songs can be stored in 1 megabyte. This can be done as follows:

Therefore, we can store 6 songs in 1 megabyte.
So, in 60 megabyte we can store the following number of songs:

So, we can store a total of 360 songs in 60 megabytes.
When parallel lines are cut by a transversal, then alternate interior angles are congruent.
Angles PXY and XYS are alternate interior angles.
m∠XYS = m∠PXY
Answer:
m∠XYS = 64.36°