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IrinaVladis [17]
2 years ago
6

A triangle has an area of 2400cm^2. The angle between two adjacent sides of the triangle is 150°. If the length of one of the ad

jacent sides is 65cm, calculate the length of the other side correct to 3 significant figures.​
Mathematics
1 answer:
GuDViN [60]2 years ago
7 0

Answer: 73.9

Step-by-step explanation:

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Does someone know how to solve this problem?
Naddika [18.5K]

Answer:

Acute scalene triangle.

Step-by-step explanation:

Acute scalene triangle.

Sides: a = 4   b = 7   c = 8

Area: T = 13.998

Perimeter: p = 19

Semiperimeter: s = 9.5

Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad

Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad

Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad

Height: ha = 6.999

Height: hb = 3.999

Height: hc = 3.499

Median: ma = 7.246

Median: mb = 5.268

Median: mc = 4.062

Inradius: r = 1.473

Circumradius: R = 4.001

Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]

Centroid: CG[3.313; 1.166]

Coordinates of the circumscribed circle: U[4; 0.071]

Coordinates of the inscribed circle: I[2.5; 1.473]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 150.005° = 150°19″ = 0.524 rad

∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad

∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad

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Answer:

6*10^8  is 200 times larger than  3*10^6

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To compare both values we divide the exponents

\frac{6*10^8}{3*10^6}

6 divide by 3 is 2

for simplify exponents we use exponential property

a^m / a^n = a^(m-n)

\frac{10^8}{10^6}=10^2

\frac{6*10^8}{3*10^6}=2*10^2= 200

6*10^8  is 200 times larger than  3*10^6

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Answer:

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